Sleuth Home - Message Boards - Newbie Questions

Oct-7-2005 11:17

Is it correct that favors are not guaranteed each day? I am not subscribed, so most days I get my 3 cases + 1 favor.

On some occasions when I've made a mistake, I haven't gotten a favor that day and have assumed it was an additional penalty along with the 'black mark.'

I can often find someone needing a favor after 2 correctly solved cases. Today, at that point nobody had anything. While working on case #3, still nobody needed a favor. I eventually had to quit that case, and still nobody was asking.

I have never been refused a favor after 3 correctly solved cases...so I'm guessing there's some type of formula involved that includes wrong guesses or quits.

Can anyone give further details?

Oct-7-2005 13:07

Mak is right, but there are loopholes. Sometimes you will get a favor after 2 correctly solved cases. ANd sometimes it takes long. Once i solved 6 cases before i got a favor. that was frustrating. But for the most part it is as Mak said,

Favor solved + 3 solved = favor
or
4 solved cases = favor

Oct-7-2005 14:56

Exactly what I was looking for, thank you to both.

Oct-7-2005 18:22

You are very welcome :)

Oct-8-2005 02:05

If you quit/falsely accuse, does the favour counter start again:

2 solved + 1 quit/error = no favour and need 3 solved = favour?
OR is it
2 solved + 1 quit/error = no favour and need only 1 more solved = favour?

Oct-8-2005 02:31

It's the last formula that counts :)

Oct-8-2005 16:18

Right! And if you are subscribed, changing cities usually restarts the favor counter. So if you have a favor for the butcher in NYC and leave town, you won't have a favor waiting for you in any other city, nor will the butcher be holding that favor for you when you get back to NY.

Oct-9-2005 17:11

and...as if its not complated enough :)

Your two favors favor counts too!

two favors ago (solved) + 3 cases +favor + 3 cases=anouther favor

However this also works:
(not responsible for any supernovas in newbies minds)
two favors ago (solved) + 4 cases +favor + 2 cases=anouther favor

or!!

two favors ago (solved) + 5 cases +favor + 1 cases=anouther favor

This is great to use before you are traveling to a new city.

*stands behind a shield barrier to hide from the super nova blast*

Oct-9-2005 23:07

Good, glad you are behind the shield, P. Rock.

Because I am most certainly not a newbie and am not sure I quite follow you on this.

If I could, it might be useful.

Care to take another shot at (a dare I say, coherent?) explanation? ; )

Or is it crystal clear, and I am just not getting it because I am tired? (Which is possible...)

Oct-10-2005 07:00

*doubles over in laughter as she tries to decipher Rock's information and looks over at the baffled Moonshh*

*takes a deep breath and straightens herself*

I think, if you read it a bit like an algebraic equation Moonshh, all those numbers up there hold the key to the mystery "I only did two cases and have a favor, yipee!"

But, like you, I'm too tired to try to work it out.

*gives Rock a big hug and leaves before she needs a tylenol*

Oct-10-2005 09:56

I understand, Rock. If, starting from scratch, I solve 3 cases but skip my favor, I could solve a 4th...do a favor...then solve just 2 more and have another favor waiting for me.

Good to see forgetfulness isn't necessarily held against a detective in these situations.

To take it a step further (and for fun to further confuse Moonshh) ;), do favors continue to pile up if they are unused? For example, if a newbie has solved 10 cases and just discovered what favors meant, could s/he find 3 consecutive favors waiting?