



What Am I Going To Do?

Heimlich VonVictor
Vigilante

Feb142011 00:51
Hey guys. This is kind of a followup to my last thread. There I asked many of you what you had done to make things any different. Here I'm asking you, "What are you going to do?"
I always tell students it's better to show not tell, so here we go!
What I'm doing Tonight I started writing a short scripted mystery that will serve as a tutorial to answer a lot of the common SM questions that people have.
How long will it take me Hopefully I will have the whole thing done in a month (but with me who knows).
What would I need for it to work I'd need it to be approved as a Scripted Mystery and ideally I'd like Ben to make it free to all players.
So what do you think guys? What can you do to help Sleuth?

Replies 
turtledove
Gopher to the Sleuth Gods

Mar232011 05:44
Thanks VS but I've already promised Ypsi that she could play ;) She actually begged poor thing. It was pathetic, lol.
For those who don't know Ypsi is me in disguise and I can't play both so Turtle has decided to sit this one out :)

Irene

Mar232011 10:44
For a future AVH tournamen, if it's team based, I would actually love to see a team made up of Ben, Sunny, Secret_Squirrel and Heigh Leigh Irregulars....
I have a vague feeling someone in Sleuthville would have seen it very inspiring to be allowed to get the chance of beating an Admin team.
(Of course, it would probably be very difficult to beat them, but it had been great to be given the ability to try). :)
(I think it's important to mention here, that you will NOT have to log in with your valueable sleuth on playsleuth2 to look at the results.)
 I have put up a page for collecting the information needed now, and will start on organizing the information so that it will be more easy to read :D

Secret_Squirrel
Safety Officer

Mar232011 15:24
Hi. I have multiple RL commitments that make the time needed for VH's almost impossible to commit to. Sorry.

Heimlich VonVictor
Vigilante

Mar232011 20:54
I'd love to participate, unfortunately, this is a very hectic time for me, and I've been traveling a lot lately. I'm actually writing this from my phone in a hotel room in Atlanta. That said, I think this is an awesome idea and I'm so happy to see the response to it. Good luck to everyone involved, and kudos to Irene for igniting the fire!

Irene

Mar242011 08:52
Here is what I have found about the "Serges" score calculation system.
First each member in originally 3 member teams, will get a "personal" score based on the number of days between hunt start and capture.
Hunt start will be the set start date, regardless of when you actually choose to start. (though starting a day early will count as failed).
Number of days will be calculated by taking the (capture day  start day), i.e. capturing on the day you started would be 0 days.
The personal score is given this way:
Number of days = 1 > points = 15
Number of days = 2 > points = 15
Number of days = 3 > points = 14
Number of days = 4 > points = 12
Number of days = 5 > points = 9
Number of days = 6 > points = 5
Other number count of days > points = 0
The team score will be based on 3 members, and the combination giving the highest score will be chosen automatically. Meaning the intention is for all members to start.
The team score will first be the sum of the "personal score" each team member is given.
If two team members finish on the same number of days, the points for finishing the day before will be added to the team score (for the first additional team member finishing on the same number of days).
If all/3 team members finish on the same number of days, the points for finishing the day before will be added to the team score for the first additional team member finishing on the same number of days. Then for the second team member finishing the same number of days, the team score is added with the points for the day before, and the points for the day before that.
Ok, let me have a couple of examples (I just show the "selected" version):
Example 1:
Member 1 finish on number of days = 5
Member 2 finish on number of days = 6
Member 3 finish on number of days = 6
Team score = sum of member points (9 + 5 + 5) + score of day before for the second one completing on the same day as another (9) = 28 points

Irene

Mar242011 09:04
Ok, minor change, after having read more thoroughly. You get the score for the following day, not the previous day. That makes example 1 wrong.
Let me try with new examples:
Member 1 finish on number of days = 3
Member 2 finish on number of days = 4
Member 3 finish on number of days = 4
Team score = member basic points(14 + 12 + 12) + bonus for first additional same day(9) = 45
Next example: all members finish on number of days = 4
Team score = member basic points (12 + 12 + 12) + bonus for first additional same day (9) + bonus for second additional same day (9 + 5) = 59.
I hope I made it right this time. If some oldies find I explained the calculation wrong, please help me correct it so that it will be right :)

Night Queen
Old Shoe

Mar242011 09:35
I am confused on the results. Afterall, we are detectives not rocket scientists. Here is my stab at the results the way I believe Irene intends:
Irene's Example 1:
Example 1:
Member 1 finish on number of days = 5
Member 2 finish on number of days = 6
Member 3 finish on number of days = 6
Team score = sum of member points (9 + 5 + 5) + 0 = 19 points
Example 2:
Member 1 finish on number of days = 3
Member 2 finish on number of days = 4
Member 3 finish on number of days = 4
Team score = member basic points(14 + 12 + 12) + bonus for first additional same day(9) = 47
Hopefully, my math is correct, or I will ask Oregon State University for my money back.

Irene

Mar242011 09:41
I am thankful there are people out there that is able to help and correct when I am doing mistakes. I agree with Night Queen here, her results are more correct than mine :D

Breitkat
Pinball Amateur

Mar242011 18:45
Umm, two slight changes, if I might:
I KNOW there was a seven (7) point score between the 9 and 5 ones (ie, day 5 had 9 points, day 6 had 7, and day 7 had 5). Might want to edit that in. Sorry.
Secondly, the way Serges ran his bonus scores was a bit complicated, but I'll see if I can give it a go (no guarantees on my success though):
Basically, each member of a team that scored on the SAME DAY received an increasing number of bonus points, one day's worth increase for each team member.
So, (for example):
Team A has a group that finishes with one member on Day 3, two who finish on Day 5, and one who finishes on Day 7. Day 3 person receives 14 points. Day 7 person receives 5 points (we stuck in 7 points for Day 6, remember? ;). But the two Day 5 people are scored differently. The team member who scored first gets 9 points. The SECOND person gets 9 points, PLUS the reward for the next day (ie, 7 points). His/her score is 16 total.
Team A's total is 44.
But let's have a look at a team that deliberately finishes all on the same day.
Team B has a group that all finishes on day 5. Member #1 gets 9 points. Member #2 gets 9 points (Day 5), plus a reward for finishing on the same day as his teammate (Day 6, 7 points), or 16 points total. Member #3 gets 9 points, plus (again) a reward for finishing on the same day as his teammates (he gets Day 6, 7 points + Day 7, 5 points), or 21 points total. Member #4 gets 9 points, plus (again) a reward for finishing on the same day as his teammates (he gets Day 6, 7 points + Day 7, 5 points + Day 8, 0 points) or 21 points total. When the four scores, 9, 16, 21, and 21 are added up...
Team B's total is 67 points.
Like I said, it was complicated. (And sometimes, it took a PhD to add up. ;) But it was designed to encourage teams to work together and (most importantly) all solve on the same day. Whether y'all want to use the system or not is up to you, but there it is.
Hope I've explained it clearly enough. ;)

Irene

Mar252011 09:00
I am happy for the update. We will go with your way of calculating points, which is basically the system I put up as well.
 just with the addition of the 7points for day 6 ;)
BUT, I have deliberatedly choosen 4member teams, and 3 of the members to give score to the teams total. This is because I want the team to cooperate, but not end up shooting at each other if one is extreemely unlucky.
So, I will make the computer calculate the team score for each possible combination of 3members within the team, and make it stick with the combination that gives the best score for the team.
This means all will set out from Shangri La, with a new Villain to catch. (preferably not start before the start date April  1), and try to make the team get a good combination of scores. Even if one of the team members end up failing his or her AVH, the team might still end up with the top score :) This is an experiment, that I do hope will encourage people. But, we need to test it to see if my suggestion is correct or not.
We won't know until we have tried.


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