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Oct-27-2005 03:36

Just wondering. Say I have two cases from the same difficulty. Assume that the payment for the first case is much higher than the payment for the second case. Does that mean that the first case is way harder than the second.

In short, does a higher "fee" mean a harder case?

Oct-27-2005 09:23

I have always suspected that there's a range of payments for each difficulty level, and the actual price for each case is randomly determined, not related to anything else.

Oct-27-2005 15:47

I know I've had cases at lower levels actually pay out more than higher level cases... go figure

Oct-28-2005 00:27

thinking of the same thing. i noticed that the price range of the "incredibly hard" and "stupendously hard" difficulties are pretty similar. i was kind of thinking settling for the incredibly hard first - they have the same price range but this one gives lower experience, hence making the unbelievable rate of inflation for the "cleaning-up fee" much slower. That would allow me to catch up, the last one making me pretty much poor...