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4 We's per case
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GrOwInG_FeAr
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Dec-7-2006 09:33
alright , the fact of having 3 WE's in 1 case caused my other detective to retire :(:(:( ... i was on a ridiculously hard case ... and i had 4 alibis i dnt know ... 1 of which i ddnt even get from the suspect .. the other 3 i do have , but i had to bribe for them ... anyways , i found a WE for one suspect , i bribed and found that he had a real alibi .... then i found another alibi belonging to the person that i ddnt even get an alibi frm , i accused and it turned out to be wrong ... so RAnstetts theory is correct ... there can be 4 WE's per case
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AraLives
Battered Shoe
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Dec-10-2006 10:01
Wow. Looks like the guilty suspect still has two WE against him, though. So I guess the moral of the story is, you can't use the absence of WE to accuse.
Perfect work there, henryc!
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GrOwInG_FeAr
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Dec-11-2006 11:24
well this has been a hot debate , but it sure cleared up loads of misconceptions:)... im pretty sure that sometime soon , someones gna get an FA for accusing someone with 2 WE's :P
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Tz_BG
Well-Connected
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Dec-11-2006 13:48
I certainly hope that doesn't happen Growing Fear as many people, myself included, rely on that formula. Though I also hope that if someone is unfortunate enough to have it happen, they get some screenshots as proof.
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reda
Well-Connected
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Dec-12-2006 01:56
I still think that innocent suspect cant have 2 WE's. I play like this for over 2 years now and never had a false on it.
?The fact that you can have many other WE's as red harrings still doesnt mean that its more than one per innocent suspect.
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Secret_Squirrel
Safety Officer
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Oct-9-2007 20:30
bumpage for DD.
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DuchessaDarling
Lucky Stiff
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Oct-9-2007 20:39
thanks, SS.
That was really helpful!
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Zoriah Bastin
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Oct-10-2007 00:15
"Point being... you CAN'T eliminate a suspect through WE UNLESS you get EVERY other suspect (except 1) to deny knowledge of them. "
I'm pretty sure this is what just happened to me though. Still not sure what I did wrong. I posted a thread about it above this one.
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Dark Raven
Trusted Informer
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Oct-11-2007 09:06
I have some insight on this subject. The number of WE in a case is equal to the number of PE +1. Every person who matches a PE will have a WE. Except the guilty party will have two.
If someone has two WE they are guilty. I've tested this theory over and over again and it's proven true.
Hope this helps a bit.
Raven.
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