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Dec-7-2006 09:33

alright , the fact of having 3 WE's in 1 case caused my other detective to retire :(:(:( ... i was on a ridiculously hard case ... and i had 4 alibis i dnt know ... 1 of which i ddnt even get from the suspect .. the other 3 i do have , but i had to bribe for them ... anyways , i found a WE for one suspect , i bribed and found that he had a real alibi .... then i found another alibi belonging to the person that i ddnt even get an alibi frm , i accused and it turned out to be wrong ... so RAnstetts theory is correct ... there can be 4 WE's per case

Dec-9-2006 08:53

I think that instances of multiple false WE are not that rare. On three cases in a row I have found 5 WE, 2 against the guilty person and three for people with valid alibis. All three cases were RH, with 7, 8, and 8 people.

I was able to ask for all of the hints in all of the cases. Everyone said to know something provided WE. Though not everyone who provided WE was identified by the townies. No one said to know nothing provided WE.

Dec-10-2006 07:58

Here is the screen shot that henryc provided for us:

http://www.freewebs.com/globalss/sleuthmythbusters.htm


It clearly shows 5 WE

Dec-10-2006 10:01

Wow. Looks like the guilty suspect still has two WE against him, though. So I guess the moral of the story is, you can't use the absence of WE to accuse.

Perfect work there, henryc!

Dec-11-2006 11:24

well this has been a hot debate , but it sure cleared up loads of misconceptions:)... im pretty sure that sometime soon , someones gna get an FA for accusing someone with 2 WE's :P

Dec-11-2006 13:48

I certainly hope that doesn't happen Growing Fear as many people, myself included, rely on that formula. Though I also hope that if someone is unfortunate enough to have it happen, they get some screenshots as proof.

Dec-12-2006 01:56

I still think that innocent suspect cant have 2 WE's. I play like this for over 2 years now and never had a false on it.
?The fact that you can have many other WE's as red harrings still doesnt mean that its more than one per innocent suspect.

Oct-9-2007 20:30

bumpage for DD.

Oct-9-2007 20:39

thanks, SS.
That was really helpful!

Oct-10-2007 00:15

"Point being... you CAN'T eliminate a suspect through WE UNLESS you get EVERY other suspect (except 1) to deny knowledge of them. "

I'm pretty sure this is what just happened to me though. Still not sure what I did wrong. I posted a thread about it above this one.

Oct-11-2007 09:06

I have some insight on this subject. The number of WE in a case is equal to the number of PE +1. Every person who matches a PE will have a WE. Except the guilty party will have two.

If someone has two WE they are guilty. I've tested this theory over and over again and it's proven true.

Hope this helps a bit.

Raven.